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RE: Identity Transformations revisited

Subject: RE: Identity Transformations revisited
From: "Karl J. Stubsjoen" <karl@xxxxxxxxxxxxx>
Date: Sat, 6 Mar 2004 10:58:35 -0700
xsl identity
This almost works:
<!-- main match for campaigns -->
<xsl:template match="campaign">
    <xsl:for-each select="*">
    	<xsl:element name="{name()}">
            <xsl:for-each select="@*">
	        	<xsl:attribute name="{name(.)}"><xsl:value-of
select="."/></xsl:attribute>
            </xsl:for-each>
        	<xsl:value-of select="."/>
        </xsl:element>
    </xsl:for-each>
</xsl:template>

But, not getting child elements.  I'm getting the value from the child
elements, but the elements themselves are stripped.  Output looks like this
(a table decleration with no TRs and TDs):

<< BEGIN SNIPPET >>
<table width="650" border="0" cellspacing="0" cellpadding="0">
                                    Simple Marketing Level One:
                                  $ 499.00 /six months
                        One Page Optimized Metatags based on Website
Content:

                                    Keyword Research:

                                            Development of keywords/phrases
based on website content

                                            Guaranteed minimum of 25 first
page listings among the major search engines

<< END SNIPPET >>


Karl

-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Karl J.
Stubsjoen
Sent: Saturday, March 06, 2004 10:39 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Identity Transformations revisited


Hello,

Previously I had asked the question on how to identity transform the a XML
that has been passed in as a parameter.  There was some mixed conclusions
whether you could or could not.  For sure, I can treat this parameter as XML
and as a result tree.

Why can't I set up a for-each... and transform on each node and attribute of
the result tree?  Maybe I can not push an apply-templates... but I should be
able to implicitly step through the source.

So I have this:

     <xsl:apply-templates select="$c"/>


A correct template match is made here:
<xsl:template match="campaign">
    <xsl:copy>
     <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
</xsl:template>

(the above doesn't seem to work...)
but couldn't I:
<xsl:template match="campaign">
    <xsl:for-each select="*">
     <xsl:copy-of select="."/>
    </xsl:for-each
</xsl:template>

(but this is where I am not sure how to appropriately write the for-each..)
Any help would be appreciated.

Karl


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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