RE: reccursive sum ?

Ok I proceed and it work fine ! I only had a bug because of the folowing
line :

		document(concat('../ME/', $refME, '.xml')

So I put it in a variable

		<xsl:variable name="PathMEXML">
			../ME/<xsl:value-of select="$refME"/>.xml
		</xsl:variable>
and then :
		document($PathMEXML)

and it work ! But i really don't understant why it did not work with the
first expression !!!??,

-----Message d'origine-----
De : owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]De la part de David
Carlisle
Envoyé : jeudi 4 mars 2004 14:39
À : xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Objet : Re:  reccursive sum ?



> So there's no solution..

oh, there's always a solution:-)

for example in your "first pass" node set you could store the sums rather
than the links (just using the "one file" form of document() ) so
something like

<xsl:variable name="ME-sum">
<xsl:for-each select="ME>
 <sum>
 <xsl:value-of
select="count(document(concat('../',@xid,'.xml'))/some/path/i/forget"/>
 </sum>
</xsl:variable>

so now $ME-sum is something like
<sum>5</sum><sum>7</sum><sum>3</sum><sum>3</sum>
including repeated sums, so you just want to sum that:

<xsl:value-of select="msxsl:node-set($ME-sum)/sum"/>

David

--
http://www.dcarlisle.demon.co.uk/matthew

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