[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Iterative variation of attributes
If it were me, I'd start by creating (by hand) a source
<source> <line/> ... <line/> </source> with the correct number of lines (easy enough to do), and iterate over that using David's solution, without needing the funky position() test: <xsl:for-each select="//line"> <line x1="{position()+15}%" yi=85%" x2="{position()+15}%" yi=15%" /> </xsl:for-each> (Sometimes brute force is the easiest solution, especially for a one-off.) On the other hand, you've probably already done it with one of the more general solutions already posted. Cheers, Wendell At 07:44 AM 3/3/2004, David wrote: so long as your source tree has at least 70 nodes, ====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ====================================================================== XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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