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Re: Iterative variation of attributes

Subject: Re: Iterative variation of attributes
From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>
Date: Wed, 03 Mar 2004 11:27:57 -0500
xslt iterate attributes
If it were me, I'd start by creating (by hand) a source

<source>
  <line/>
   ...
  <line/>
</source>

with the correct number of lines (easy enough to do), and iterate over that using David's solution, without needing the funky position() test:

<xsl:for-each select="//line">
 <line x1="{position()+15}%" yi=85%" x2="{position()+15}%" yi=15%" />
</xsl:for-each>

(Sometimes brute force is the easiest solution, especially for a one-off.)

On the other hand, you've probably already done it with one of the more general solutions already posted.

Cheers,
Wendell

At 07:44 AM 3/3/2004, David wrote:
so long as your source tree has at least 70 nodes,

<xsl:for-each select="(//node()}[position() &lt;= 70]">
 <line x1="{position()+15}%" yi=85%" x2="{position()+15}%" yi=15%" />
</xsl:for-each>


======================================================================
Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
----------------------------------------------------------------------
  Mulberry Technologies: A Consultancy Specializing in SGML and XML
======================================================================


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