[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: binding xml to stylesheet
Hello, I think I was a bit vague the first time and I apologise if this is painfully obvious. If I have <?xml version="1.0" encoding="utf-8"?> <?xml-stylesheet href="stylesheet.xsl" type="text/xsl"?> <Company> <Name>Hello Tours</Name> <Location>Dublin</Location> </Company> <Company> <Name>Bonjour Voyages</Name> <Location>Paris</Location> </Company> and <?xml version = "1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="html" indent="no" omit-xml-declaration="yes"/> <xsl:template match="/"> <table> <xsl:apply-templates/> </table> </xsl:template> <xsl:template match="Company"> <tr><td><b>Name:</b><i><xsl:value-of select="Name"/></i></td></tr> <tr><td><button onClick="getLocation()" >Click Me!</button></td></tr> </xsl:template> </xsl:stylesheet> can I write a getLocation() function that will reside in the resultant document and that will do something like document.parentDocument.getElementsByTagName("Location") if not, why not? Where has the original document gone? Cheers, Donal If a document has been created by binding an XML doc to a stylesheet, is it possible to refer to elements in the original XML document? I'm looking for something like - document.parentDocument.getElementsByTagName("Location") for example. If not, why not? ___________________________________________________________ Yahoo! Messenger - Communicate instantly..."Ping" your friends today! Download Messenger Now http://uk.messenger.yahoo.com/download/index.html XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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