RE: using variable in xsl:include ?

It doesn't work because expanding xsl:include is the first thing the XSLT
processor does, long before it ever starts reading a source document. Like
other programming languages, XSLT stylesheets are compiled first, then
executed, and you can't change the program in the middle of the execution
phase.

At another level, it doesn't work because the content of the href attribute
is a URI, not an XPath expression.

Michael Kay

# -----Original Message-----
# From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-
# list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Nikolas Nehmer
# Sent: 26 February 2004 11:11
# To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
# Subject:  using variable in xsl:include ?
# 
# Hi,
# 
# is it possible to use a variable in xsl:include like e.g.
# <xsl:variable name="home_directory"
# select="document('../../XML/config.xml')//iese.config:home_directory"/>
# <xsl:include
# href="concat('file://',$home_directory,'class/Person/XSL/person_short.xs
# l')"/>
# 
# This example does not work! Does anyone know why? The parser says
# something like wrong syntax for pathnames,... Any suggestions?
# 
# Best regards,
# Nick
# 
# 
#  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list