[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: sorting information from multiple files
document() will accept a node set rather than a string so if it wasn't for the " " "-" translation you could replace <xsl:for-each select="child::category"> <xsl:variable name="catnamemod" select="translate(name,' ','_')" /> <xsl:for-each select="document($nsindex/*[name()=$catnamemod])/root/child::*"> <xsl:if test="@topfive=true()"> by <xsl:for-each select="document($nsindex/*[name()=current()/category/name])/root/child::*[@topfive]"> Is it not possible to arrange that your nsindex variable has the right names (by doing the translation at the point you construct that variable? it's inconvenient to do the translation later as that is a string based function which stops you using the implicit existential quantification over a node set that you get with =. -- http://www.dcarlisle.demon.co.uk/matthew ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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