RE: Loops and variables question

Thank you, this was exactly what I want!!

-----Mensaje original-----
De: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]En nombre de
Jarno.Elovirta@xxxxxxxxx
Enviado el: jueves, 27 de noviembre de 2003 13:15
Para: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Asunto: RE:  Loops and variables question


Hi,

> I want to build a list with the quantity attribute of the all
> ROOMS nodes.
> I have this XML:
>
> <ROOMS>
>  <ROOM quantity="5">
>  <ROOM quantity="3">
>  <ROOM quantity="7">
> </ROOMS>
>
> My desired output is:
> 1,2,3,4,5,1,2,3,1,2,3,4,5,6,7
>
> I tryed with an auxiliary variable <xsl:variable
> name="num"...>but I can
> increment this variable for each node.

No you can't, variables are immutable in XSLT once bound.

  <xsl:output method="text"/>
  <xsl:strip-space elements="*"/>
  <xsl:template match="ROOM" name="counter">
    <xsl:param name="i" select="1"/>
    <xsl:if test="$i &lt;= @quantity">
      <xsl:value-of select="$i"/>
      <xsl:if test="not(not(following-sibling::ROOM) and $i =
@quantity)">,</xsl:if>
      <xsl:call-template name="counter">
        <xsl:with-param name="i" select="$i + 1"/>
      </xsl:call-template>
    </xsl:if>
  </xsl:template>

Cheers,

Jarno - Velvet Acid Christ: Angels In Bondage (B-Side / mp3 128 Mix / by
Angels In Bondage)

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 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list