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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Can not convert #STRING to a NodeList! Error..
 In my XSL, from the parent template I load a XML file using document() function. and I pass this as parameter to child templates. <xsl:call-template name="main"> <xsl:with-param name="labelsfile" select="document('English.xml')"/> </xsl:call-template> In my child templates, I am retrieving using <xsl:param name="labelsfile"/> I also have declared a key(xsl:key) in the importing xml file in my xsl.
<xsl:for-each select="$labelsfile">
<xsl:value-of select="key('label','ecollab.businessfollowedby')" />
</xsl:for-each>when I transform this using my java program, I get the following exception. Can not convert #STRING to a NodeList! I want to know why we get this error usually. please help regards s.arun prasath _________________________________________________________________ Make fun prints Click here to order. http://www.kodakexpress.co.in Delivery anywhere in India. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
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