Re: recursive call of template - how to find parents

Hi Michael,

> It is that way, because I still used my old sitemap template, which
> you recommended to replace with the sitemap template you wrote. So I
> did replace also the sitemap template. And now, I get a stack
> overflow error, when I try to generate the homepage.

That usually indicates infinite recursion, but I can't see anything in
the code I recommended that would give you infinite recursion. I
tried:

XML document:
<homepage>
  <topic name="point1" filename="asdf">   
    <topic name="subpoint1" filename="asdf1">       
      <topic name="subsubpoint1" filename="asdf2">           
        <topic name="subsubsubpoint1" filename="asdf3" />
      </topic>
    </topic>
    <topic name="subpoint2" filename="asdf4" />
  </topic>
  <topic name="point2" filename="asdf5" />
  <topic name="point3" filename="asdf6" />
  <topic name="point4" filename="asdf7" />
</homepage>

XSLT:
<xsl:stylesheet version="1.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output indent="yes" />

<xsl:template match="/">
  <xsl:call-template name="sitemap" />
</xsl:template>

<xsl:template name="sitemap">
  <ul>
    <xsl:apply-templates select="homepage/topic" />
  </ul>
</xsl:template>

<xsl:template match="topic">
  <li>
    <a>
      <xsl:attribute name="href">
        <xsl:for-each select="ancestor-or-self::topic">
          <xsl:value-of select="@filename" />
          <xsl:if test="position() != last()">/</xsl:if>
        </xsl:for-each>
      </xsl:attribute>
      <xsl:value-of select="@name"/>
    </a>
    <xsl:if test="topic">
      <ul>
        <xsl:apply-templates select="topic"/>
      </ul>
    </xsl:if>
  </li>
</xsl:template>

</xsl:stylesheet>

and got, as the result:

<ul>
   <li>
      <a href="asdf">point1</a>
      <ul>
         <li>
            <a href="asdf/asdf1">subpoint1</a>
            <ul>
               <li>
                  <a href="asdf/asdf1/asdf2">subsubpoint1</a>
                  <ul>
                     <li>
                        <a href="asdf/asdf1/asdf2/asdf3">subsubsubpoint1</a>
                     </li>
                  </ul>
               </li>
            </ul>
         </li>
         <li>
            <a href="asdf/asdf4">subpoint2</a>
         </li>
      </ul>
   </li>
   <li>
      <a href="asdf5">point2</a>
   </li>
   <li>
      <a href="asdf6">point3</a>
   </li>
   <li>
      <a href="asdf7">point4</a>
   </li>
</ul>

So I guess the problem is somewhere that you haven't shown us.

Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


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