[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] saxon 7.6.5 in SMLSpy 5 rel. 4 and xsl:result-document
Hi, I am using XMLSpy 5 rel. 4 and saxon 7.6.5 as XSLT Processor. I do this with the following instruction in Tools > Options... > XSL java -cp D:\Programme\net\sourceforge\saxon\7.6.5\saxon7.jar net.sf.saxon.Transform -o %2 %1 %3 I am using j2sdk1.4.2. When I process the following xsl file from within XMLSpy, I get no error message but I also don't get the file "concat.result.xml". Everything works as expected when I call saxon from the comand line. Anybody know what I'd doing wrong? Thanks a lot. Erwin ------------ concat.xsl ------------ <?xml version="1.0" encoding="UTF-8"?> <?xmlspysamplexml D:\projects\ehecatl\web\xml\concat.xml?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output name="xml-format" method="xml" indent="yes"/> <xsl:template match="/"> <xsl:result-document href="concat.result.xml" format="xml-format" > <xsl:text disable-output-escaping="yes"> <top> </xsl:text> <xsl:for-each select="/concat/file"> <xsl:copy-of select="document(@source)"/> </xsl:for-each> <xsl:text disable-output-escaping="yes"> </top> </xsl:text> </xsl:result-document> </xsl:template> </xsl:stylesheet> ------------ concat.xml ------------ <?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xsl" href="D:\projects\ehecatl\web\xml\concat.xsl"?> <concat xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="concat.xsd"> <file source="file1.xml"/> <file source="file2.xml"/> <file source="file3.xml"/> </concat> .............................. Erwin Kloeck Produktentwicklung Oestreicher + Wagner Medientechnik GmbH Frankenthaler Strasse 20 D-81539 Muenchen Fon +49 (0)89-68961 216 Fax +49 (0)89-68961 271 XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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