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RE: Date Format in XSLT

Subject: RE: Date Format in XSLT
From: "Michael Kay" <mhk@xxxxxxxxx>
Date: Thu, 4 Sep 2003 15:41:25 +0100
xslt date format
If the names are all three characters, use

substring("JanFebMarApr....", ($month-1)*3+1, 3)

Michael Kay

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> michel geadah
> Sent: 04 September 2003 13:47
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Date Format in XSLT
> 
> 
> hi,
> 
> I need to transform the month to words.
> For example, if i have '1' i need to output 'Jan', if i have 
> '2' i need to 
> output 'Feb', and so on...
> (That is to say if i have 1-12-2003 i need it to be transformed to 
> 1-Dec-2003)
> 
> Thanks...
> Michel
> 
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