[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Display value AND apply templates
Try this <xsl:template match="/"> <xsl:apply-templates /> </xsl:template> <xsl:template match="para"> <p> <xsl:apply-templates /> </p> </xsl:template> <xsl:template match="chem"> <span class="chem> <xsl:apply-templates /> </chem> </xsl:template> <xsl:template match="sub"> <sub> <xsl:apply-templates /> </sub> </xsl:template> <xsl:template match="text()"> <xsl:value-of select="." /> </xsl:template> ----- Original Message ----- From: "Drew McLellan" <dru@xxxxxxxxxxxxxxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Monday, August 11, 2003 1:45 PM Subject: Display value AND apply templates > I've been looking at this for too long and can no longer think clearly. Take this example: > > <myxml> > <para>The notation for water is > <chem>H > <sub>2</sub> > 0 > </chem> > </para> > </myxml> > > I'm trying to transform to XHTML. The desired output for the above would be: > > <p>The notation for water is <span class="chem">H<sub>2</sub>0</span></p> > > The problem I have is that if I use value-of "." I can get the value of node, but no further templates are applied. If I use apply-templates "*" I get the sub-templates but no value. > > For example: > > <xsl:template match="chem"> > <span class="chem"><xsl:apply-template select="*" /></span> > </xsl:template> > > <xsl:template match="sub"> > <sub><xsl:value-of select="." /></sub> > </xsl:template> > > This gets the <sub> but loses the value of the <chem>. > > As I say, I've lost all clarity of mind on this, so I'm expecting it to be obvious! Any and all suggestions most welcome. > > Thanks for your time. > > Drew McLellan > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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