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AW: Sorting and re-ordering down a hierarchy

Subject: AW: Sorting and re-ordering down a hierarchy
From: "Zink, Juergen" <Juergen.Zink@xxxxxxxxxxxxxxxxxxxx>
Date: Tue, 22 Jul 2003 10:45:10 +0200
xslt node ordering
Hi,

>Does anybody else have a solution, and can anyone tell me why my solution 
>does not work?

><xsl:template match="input">
>	<xsl:apply-templates select="node">
>		<xsl:sort select="node/rank" data-type="number"
order="ascending"/>
>	</xsl:apply-templates>
></xsl:template>

The statement select="node" defines the set which is sorted.
You have different call to the template with different sets.
Each is sorted. Where is the problem?

Regards,

Juergen



XSL, input, output just keeping.

<xsl:template match="/">
	<output>
	<xsl:apply-templates select="input"/>
	</output>
</xsl:template>

<xsl:template match="input">
	<xsl:apply-templates select="node">
		<xsl:sort select="node/rank" data-type="number"
order="ascending"/>
	</xsl:apply-templates>
</xsl:template>

<xsl:template match="node">
	<node>
	<xsl:copy-of select="rank"/>
	<xsl:apply-templates select="node">
	<xsl:sort select="node/rank" data-type="number" order="ascending"/>
	</xsl:apply-templates>
	</node>
</xsl:template>


><input>
><node>
>     <rank>2</rank>
>     <node>
>         <rank>88</rank>
>     </node>
>     <node>
>         <rank>7</rank>
>     </node>
>     <node>
>         <rank>66</rank>
>     </node>
></node>
><node>
>     <rank>1</rank>
>     <node>
>         <rank>3</rank>
>     </node>
>     <node>
>         <rank>2</rank>
>     </node>
>     <node>
>         <rank>1</rank>
>     </node>
></node>
></input>

The output I get on this is:
<output>
  <node>
    <rank>1</rank>
    <node>
      <rank>3</rank>
    </node>
    <node>
      <rank>2</rank>
    </node>
    <node>
      <rank>1</rank>
    </node>
    </node>
    <node>
      <rank>2</rank>
    <node>
      <rank>88</rank>
    </node>
    <node>
      <rank>7</rank>
    </node>
    <node>
      <rank>66</rank>
    </node>
  </node>
</output>



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