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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Transforming XML to XML (diff. format) using XSL
 Hello to you all,
I am using the following XSL processor:
Vendor: Microsoft
Vendor URL: http://www.microsoft.com
I trying to transform a XML file (created from a MySQL DB) into another
XML file listing FIXED bug details in a table and a brief description in an
order list . Problem: how do I use <xsl:for-each select=""> to refer to
each of the field names in the source? I would like to say display the
value of "bug_id" inside the <li> tag within a ordered list and create a
hyperlink to the bug page inside the table . Please look at my XSL file.
Here is a snippet of the source XML:
<?xml version="1.0"?>
<mysqldump>
<database name="bugtracker">
<table name="phpbt_bug">
<row>
<field name="bug_id">1</field>
<field name="title">Contacts Disappearing from Distribution Lists</
field>
<field name="description">If a contact us updated from the
&quot;Edit Contact&quot; screen then they are somehow removed from
any distribution lists they were on.</field>
<field name="url"/>
<field name="severity_id">5</field>
<field name="priority">1</field>
<field name="status_id">7</field>
<field name="resolution_id">1</field>
<field name="database_id">0</field>
<field name="site_id">0</field>
<field name="assigned_to">5</field>
<field name="created_by">1</field>
<field name="created_date">1049903813</field>
<field name="last_modified_by">1</field>
<field name="last_modified_date">1052321523</field>
<field name="project_id">1</field>
<field name="version_id">6</field>
<field name="component_id">5</field>
<field name="os_id">1</field>
<field name="browser_string">Mozilla/4.0 (compatible; MSIE 6.0;
Windows NT 5.1)</field>
<field name="close_date">1052321523</field>
<field name="closed_in_version_id">12</field>
<field name="to_be_closed_in_version_id">12</field>
</row>
<row>
[A lot more rows....................................................]
==========================================================================================================
My XSL file:
<xsl:output method="xml" version="1.0" encoding="ISO-8859-1" indent="yes"/>
<xsl:template match="/">
<xml>
<document>
<properties><author email="vipul.vij@xxxxxxxxxx">Vipul Vij</
author></properties>
<body>
<section name= "Bugs fixed">
<p>Summary of bugs that have been now fixed</p>
<xsl:for-each select="mysqldump/database/table/row"> <!
--*********************************************************************-->
<xsl:for-each select="field">
<!-- THIS IS NOT READING AND CREATING THE ORDER LIST -->
<xsl:sort select="bug_id"/>
<!--
*********************************************************************-->
<xsl:if test= "status_id='7'">
<xsl:if test="resolution='1'">
<ol>
<li><xsl:value-of select="title"/></li>
</ol>
</xsl:if>
</xsl:if>
</xsl:for-each>
</xsl:for-each>
<table>
<tr>
<td>Bug ID</td>
<td>Name</td>
<td>Description</td>
<td>Fixed by</td>
</tr>
<xsl:for-each select="mysqldump/database/table/row">
<!-- *********************************************************************
-->
<xsl:sort select="bug_id"/>
<!-- NOT READ IN CORRECTLY AND NOT CREATING TABLE
<xsl:if test="status_id=7">
<!-- ROWS
-->
<xsl:if test="resolution=1">
<tr>
<td><A HREF= "
http://intranet/phpbt-0.9.1/bug.php?op=show&bugid="><xsl:value-of
select="bug_id"/><xsl:value-of select="bug_id"/></A></td>
<td><xsl:value-of select="title"/></td>
<!--- Need to use <p> tags</p> in
description-->
<td><xsl:value-of select="description"/></
td>
<td><A HREF="mailto:vipul.vij@xxxxxxxxxx";>
Vipul Vij</A></td>
</tr>
</xsl:if>
</xsl:if>
</xsl:for-each>
</table>
</section>
</body>
</document>
</xml>
</xsl:template>
</xsl:stylesheet>
===========================================================================================================================================================
Your help will be appreciated.
Regards,
Vipul Vij
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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