[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Extracting link information from xml document and
Jarno, - thank you very much. The following line of code worked: <a href="{.}"> <xsl:value-of select="."/> </a> Much appreciated. Brenda xsl-list@xxxxxxxxxxxxxxxxxxxxxx wrote: < < Hi, < < > <location> http://someserver.ie</location>. < > < > I want to retrieve the URL information and display it as a < > hyperlink in the browser. < > < > Currently, I can view the URL information but it is not a hyperlink. < > < > I thought of using the following:- < > <xsl:template match="technical/location"> < > <a href="http://{@link}"><xsl:value-of select="."/></a> < > </xsl:template> < > < > I will be searching different documents so hardwiring in the < > URL where it says "@link" would not provide a solution for < > me. I think that if I could declare a variable in xsl to < > store the retrieved data and then get at the contents of this < > variable within the <a href...> tag - this would provide a solution. < < <a href="{.}"> < <xsl:value-of select="."/> < </a> < < if the source is as you showed above. If the location of the URL varies, try something like < < <a> < <xsl:attribute name="href"> < <xsl:choose> < <xsl:when test="..."> < ... < </xsl:when> < ... < </xsl:choose> < </xsl:attribute> < <xsl:value-of select="."/> < </a> < < Cheers, < < Jarno - Front Line Assembly: Virus (Counterized Mix) < < XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list < < XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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