[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] How to get the Browser URL within XSL?
Hy all, First of all I do not know if this is a pure xsl or cocoon question so i mail it to both lists. I know I can access the request parameters of the url in xsl using the xsl-with-parameters type in my sitemap, but how can I get the whole URL string in xsl. The reason why I need to get this, is that I have the following URL structure: http://www.somwhere.de/test/program.html?id=300&lang=ger and I want to change the lang value to another value (eng i.e.) by clicking on my flag symbol, the problem is that I don't know the sitename in front of .html, because I just want to change the lang parameter the rest should be the same, depending on the last requested url (or is it possible to get this value inside xsl?) ! I'm using Cocoon 2.03 on tomcat4.1. Any help is welcome. Regards, Steve XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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