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RE: position() seems always to be 1

Subject: RE: position() seems always to be 1
From: Jarno.Elovirta@xxxxxxxxx
Date: Wed, 28 May 2003 09:05:35 +0300
xsl self position
Hi,

> > Above, the position() returns the context position of the 
> > self:node() locations step, and will always return 1; last() 
> > will also always return 1 as the context size for self::* 
> > will never exceed 1. Thus, the above predicate test will 
> > always return true.
> 
> That makes sense, but then why does his test
> 
> > 	<xsl:when test="self::node()[position()=last()]">
> 
> always return false?  1 = 1, so you would expect the above to
> be true.  Yet Steve says that instead of the <xsl:when> clause,
> "it always uses the otherwise" clause.

I must have misread his question then, but the Expression above will always return true.

Cheers,

Jarno - Xorcist: I Just Want to Learn

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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