RE: nodes having same values in same order

The first time you asked this you said "no extensions". The fact that
you got no answers probably means that this is very hard to do without
extensions.

The problem is actually underspecified. What do you mean for two
elements to be "the same". Just the same name? Or the same value as
well?

Here's an XPath 2.0 solution:

select="//yyy[some $x in //xxx satisfies deep-equal(., $x)]"

I'm afraid I'm too busy writing XSLT 2.0 specs right now to spend time
finding a 1.0 solution for you!

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Leena Kulkarni
> Sent: 10 April 2003 14:45
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  nodes having same values in same order
> 
> 
> Hello,
> 
> If I have a structure like the following -
> 
> <xxx>
>   <pp></pp>
>   <qq></qq>
>   <rr></rr>
> </xxx>
> <xxx>
>   <pp></pp>
>   <qq></qq>
> </xxx>
> 
> <yyy>
>   <pp></pp>
>   <qq></qq>
> </yyy>
> <yyy>
>   <pp></pp>
>   <qq></qq>
>   <rr></rr>
> </yyy>
> 
> How do I find out the yyy elements that have exactly
> the same elements(same order and count) as in xxx?
> 
> Thanks
> 
> 
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