Re: Date Range in XSL

02/16/2003

as there are not 16 months in the year I'll assume that this
is dates in the rather bizarre  month-day-year order.

number(concat(substring(date,7),substring(date,1,2),substring(date,4,2))))
gives you (if I got the right indices)
numbers like 04/15/2003 --> 20030415  that you can compare with < or
sort with xsl:sort etc.

Using ISO date format of 2003-04-15 would make processing easier in
XSLT2 (and XML schema) which have native support for ISO dates, and make
the file far more easily understandable in most parts of the world)

David

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