[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: line feeds when outputing as text
Use: <xsl:value-of select="concat(@url, '
')"/> ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL "Sam Carleton" <sam@xxxxxxxxxxxxxx> wrote in message news:20030303201331.GA14537@xxxxxxxxxxxxxxxxxxx > Folks, > > I have an xml file that contains item elements. Some items have an > url attribute. I am trying to write a xslt program to give me each > url on a separate line. I figured this would work: > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > > <xsl:output method="text" indent="yes"/> > > <xsl:template match="/"> > <xsl:apply-templates select=".//item[string-length(@url)!=0]"/> > </xsl:template> > > <xsl:template match="item"> > <xsl:value-of select="@url"/> > </xsl:template> > > </xsl:stylesheet> > > The problem with this is that there is no line breaking between the > different URL's. I tried adding both a and (forgetting > which one UNIX likes): > > <xsl:template match="item"> > <xsl:value-of select="@url"/> > </xsl:template> > > And that still had no effect. Finally I tried to tack something on > the front and that DID work: > > <xsl:template match="item"> > :<xsl:value-of select="@url"/> > </xsl:template> > > I could live with this except for the fact that there is no line on > the last entry so my shell script is not picking up the last entry. > How do I get a linefeed at the end? > > Sam > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|