[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Select entire XML doc
> From: Wendell Piez [mailto:wapiez@xxxxxxxxxxxxxxxx] > Sent: Tuesday, March 04, 2003 9:53 AM > Subject: RE: Select entire XML doc > > > Brian, > > At 07:03 PM 3/3/2003, you wrote: > >Remember that the transformation works on a > >parsed XML input tree--not the raw document. So any child > of the root node > >that isn't an element is removed, and if there is more than one child > >element of the root node, the document is rejected by the > parser as being > >malformed XML. > > < snip > > > Given the root node / as context, <xsl:copy-of select="*"/> > fails to copy > these nodes (comments and PIs) since it only selects elements > (of which, > you are correct, there will be exactly one). But > select="node()" picks up > these other nodes. <xsl:copy-of select="*"/> will of course > pick up PIs and > comments that are *inside* the document element (since it's a > deep copy), > which may be part of the confusion. Thanks for the clarification on this. Normally all I would want when doing a copy are elements. I didn't realize that you *can* copy all nodes in a source document, probably because there's little point in doing so since you would just create an exact copy of the source. Perhaps if you were copying multiple sources to the result tree and wanted everything, including the <?xml?> declaration--but then the result wouldn't be well-formed XML, correct? cheers, b. | brian martinez brian.martinez@xxxxxxxx | | senior gui programmer 303.708.7248 | | trip network, inc. fax 303.790.9350 | | 6436 s. racine cir. englewood, co 80111 | | http://www.cheaptickets.com/ http://www.trip.com/ | XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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