[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: position() and last() problem
ancestor::con:view[1] selects a node list of at most 1 node so position()=1=last() always so the above would be equivalent to ancestor::con:view[1][position()=last()] I thought you had written ancestor::con:view[1][position()!=last()] which will always selct an empty node set as position() and last() are both 1 so never not equal. However U see you have written "ancestor::con:view[1][position()]!=last()" which is legal but compares the numeric value of the data content of the parent con:view element against the number of nodes in the current node list at the point the xsl:if is evaluated. [position()] is short for [position()=position()] which is always true so the above is "ancestor::con:view[1]!=last()" which is "parent::con:view != last()" This almost certainly isn't what you want to do. If I understand your problem you want to know if the parent has a following sibling test="parent::*/following-sibling::*" David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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