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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: & replacemnt?
 Thanks for your answer, yes you are right about the source, it is wrongly encoded. Actualy, I have a source file in html containing these escaped sequences in the correct form (’ in this case) but when I use xerces to create the XML document using the html as a source, the serializer gives me these double escaped sequences. Maybe it is because it is reading the characters one by one so when it sees the & character it translates it to & then the following characters are put as is. Here is the java source code to generate the XML file (only the concerned method):
protected void create(Document xmldoc){
FileOutputStream fos = null;
try{
// Write To File
fos = new FileOutputStream(filename);
// XERCES 1 or 2 additionnal classes.
OutputFormat of = new OutputFormat("xml",OUTPUT_FORMAT,false);
of.setIndent(1);
of.setIndenting(true);
XMLSerializer serializer = new XMLSerializer(fos,of);
// As a DOM Serializer
serializer.asDOMSerializer();
serializer.serialize( xmldoc.getDocumentElement() );
fos.close();
} catch(Exception ex){
ex.printStackTrace();
System.out.println("Error:" + ex.getClass().getName() +":"+ ex.getMessage());
} finally {
try{ fos.close();} catch(Exception ex){System.out.println("Can't close XML file outputstream");}
}
}
I guess that this code is responsible for the doule escaping.
I would be thankful for any help.
regards
Camille
> -----Original Message-----
> From: David Carlisle [mailto:davidc@xxxxxxxxx]
> Sent: lundi 2 décembre 2002 18:15
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: & replacemnt?
>
>
> I have a source xml file containing data as:
> <html>
> <b>Gamme de vitrages d&#8217;allčges opacifiés </b>
>
> _why_ is your source like that. &#8217; is the XML syntax for the
> 7 characters & # 8 2 1 7 ;
> is there any reason that your source does not look like
>
> <html>
> <b>Gamme de vitrages d’allčges opacifiés </b>
>
> which is what you intended, I think.
>
>
> If you must use the replace template then you eant to replace 7
> characters by 1, so that is
>
> <xsl:param name="from" select="'&#8217;'"/>
> <xsl:param name="to" select="'’'"/>
>
> Note you are _not_ trying to replace & by &.
>
> However it would be much better to fix your source files.
>
>
> David
>
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