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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: & replacemnt?
 I have a source xml file containing data as: <html> <b>Gamme de vitrages d&#8217;allèges opacifiés </b> _why_ is your source like that. &#8217; is the XML syntax for the 7 characters & # 8 2 1 7 ; is there any reason that your source does not look like <html> <b>Gamme de vitrages d’allèges opacifiés </b> which is what you intended, I think. If you must use the replace template then you eant to replace 7 characters by 1, so that is <xsl:param name="from" select="'&#8217;'"/> <xsl:param name="to" select="'’'"/> Note you are _not_ trying to replace & by &. However it would be much better to fix your source files. David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Scanning Service. For further information visit http://www.star.net.uk/stats.asp or alternatively call Star Internet for details on the Virus Scanning Service. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
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