[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Outputting dynamically
Hi Juan, With your > <xsl:param name="attr" select"'itemid|desc'"/>, i assume that you want to select the attributes itemid "or" desc. In which case, for the following code, you would get an output: 145 hammer 145 nails <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:param name="node-names" select="'itemid|desc'"/> <xsl:template match="/"> <xsl:variable name="attr1" select="substring-before($node-names,'|')"/> <xsl:variable name="attr2" select="substring-after($node-names,'|')"/> <xsl:for-each select="//@*[name() = $attr1 or name() = $attr2]"> <xsl:value-of select="."/><br/> </xsl:for-each> </xsl:template> </xsl:stylesheet> HTH Vasu ----- Original Message ----- From: "Juan Carlos Gonzalez" <jcgonz@xxxxxxxxx> To: <XSL-List@xxxxxxxxxxxxxxxxxxxxxx> Sent: Wednesday, November 06, 2002 2:35 PM Subject: Outputting dynamically > Hi: > > I want to pass the node attributes name as an > parameter to the XSLT file to transform a XML file. > For example: > > <customer id="1"> > <order id="122" > > <orderdet date="12/12/02"> > <item itemid="145" desc="hammer" qty="2"/> > <item itemid="145" desc="nails" qty="6"/> > </orderdet> > </order> > </customer> > > Then I would have in the XSLT file something like or > if someone can come with a better idea: > > <xsl:param name="attr" select"'itemid|desc'"/> > > and based on that I want to ouput only these > attributes being passed. > Any suggestions, > thanks. > > __________________________________________________ > Do you Yahoo!? > HotJobs - Search new jobs daily now > http://hotjobs.yahoo.com/ > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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