[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] [xsl-fo] generating the correct number of columns for
Hi all, I need to generate a table in xsl-fo from an html table. My problem is that in FO, you need to declare the number of columns before starting the body. On the FAQ, I only found the (enlightening) discussion on how to get the maximum number of child nodes (http://www.biglist.com/lists/xsl-list/archives/200101/msg00177.html), but the resulting code gives a number and I don't know how to use that. My question is: if I have a number (say "8"), how do I loop through to generate 8 times the line : <fo:table-column column-width="2cm"/> ? thanks for any help. Camille XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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