Re: Using document()

I'm using the XLink model so my hrefs are URIs. In the example I gave,
it's a fragment identifier which should be expanded relative to the
source document (I understand xpointer to allow this). I'm assuming that
'#someval' is still a shortcut which points to some element with an id
value of 'someval'.

From http://www.w3.org/TR/xslt#function-document:

If the URI reference does not contain a fragment identifier, then a
node-set containing just the root node of the document is returned. If
the URI reference does contain a fragment identifier, the function
returns a node-set containing the nodes in the tree identified by the
fragment identifier of the URI reference.

This suggests to me that if I use <xsl:apply-templates
select="document('#id2')" />, I should get the node of the source
document which has an id attribute equal to 'id2'. In the same way, it
suggests that if I use <xsl:apply-templates
select="document('somefile.xml#id2')" />, I should get the node whose id
is 'id2' in 'somefile.xml' which is a sibling to the source document.

So my question is assuming that there is a node with an id (in this case
an id attribute) with a value of 'id2' in my source document can I
reasonably expect the following to be equivalent:

<xsl:apply-templates select="document('#id2')" />

<xsl:apply-templates select="//*[@id='id2']" />

And the following to be true:

generate-id(document('#id2')) = generate-id(//*[@id='id2'])

Before I go and start telling excelon that they seem to have a bug in
their product, I want to make sure I'm right in my assumption (if not,
I'm going to have to re-evaluate how I do things).

Adam

-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Richard Lander
Sent: October 8, 2002 2:00 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: Using document()


The XSLT processor is looking for a resolvable path as the argument to the document function.

If the value of the xlink:href attribute is a path to an actual XML file, then it should work. If it isn't, and it's an IDREF-type link to attribute that contains that value, then you'll need an XPath that will get that value for you.

w/o more information on your document structure ... It is a little hard on this end ...

Rich

-----Original Message-----
From: Adam van den Hoven [mailto:list@xxxxxxxxxxxxxxxxxxx] Sent: Tuesday, October 08, 2002 1:50 PM
To: XSL Mailing list

Sorry if this appears twice, I'm having some problems with my mail systems.

I have a question.

I want to use the following:

<xsl:apply-templates select="document('#id2')" />

Ok, I'd never actually use this. In reality its something like:

<xsl:apply-templates select="document(@xlink:href)" />

which is likely to contain simply fragment identifiers since I'm using XLinks to normalize a sitemap hierarchy.

When I try to run this as part of a transform, I get an error saying that the file (fully resolved to refer to the source doc) cannot be found. Is this a problem with how I'm doing things or perhaps a problem with app I'm using to develop templates with (Stylus Studio)?

Do you have any other ideas about how I can accomplish the same thing given that some of my xlink:href attributes will point to external documents?

Thanks, H. Adam van den Hoven

Web Developer

Credit Union Central of BC

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