[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: document() loops
<xsl:for-each select="document(/univ-xml-list/univ-xml[1])"> <xsl:variable name = "element-name" select="name(.)"/> <xsl:element name="$element-name"> </xsl:element> </xsl:for-each> this will create all the elements that are in the first elements.. No it won't as I said before that for-each is iterating over a single node so it will only create one element, with name equal to teh name of teh node selected in the xsl:for-each select=" however that node is a document node, so has name "" so the xsl:eleemnt should generate an error thatyou are trying to generate an element with an invalid name, "". David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Scanning Service. For further information visit http://www.star.net.uk/stats.asp or alternatively call Star Internet for details on the Virus Scanning Service. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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