[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] catch from another node with the same id (NEWBIE)
Hello First let me say thank you for all the great help you are to me. again I have a nifty problem (nifty for me) peace of cake for you!? I have a for-each where I select the <produkt>'s id attribute <xsl:for-each select="/page/info/massnahmen/ratierliche/entnahmen/massnahme"> ..... <fo:table> ..... <xsl:for-each select="*/produkt"> <fo:table-row> <fo:table-cell> <fo:block> <xsl:value-of select="@id"/> </fo:block> </fo:table-cell> </fo:table-row> </xsl:for-each> .... </fo:table> .... </xsl:for-each>
instead of the "id" i need the product name (bezeichnung) which is stored in a completly different node "/page/info/produkte/" but with the correspondending "id" <page> <info> <produkte> <produkt id="1" bezeichnung="Produkt A"> <text>Produktebeschrieb A</text> </produkt> <produkt id="2" bezeichnung="Produkt B"> <text>Produktebeschrieb B</text> </produkt> <produkt id="3" bezeichnung="Produkt C"> <text>Produktebeschrieb C</text> </produkt> ........ </produkte </info> </page> can I use some kind of variable to do it? Or how do I get the correspondending "bezeichnung" attribute from the other node? Any hints? Thank you! thomas XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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