[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Getting the XPath of a node
Dennis wrote: > Hi All, > > Is there any way to get the XPath of a particular > element and attribute in match template??? > > Say if I have following XML: > <Person id="12345"> > <Name>Dennis</Name> > <Company>Netscape</Company> > <Address>Mountain View</Address> > <Email>dennis@xxxxxxxxxxxx</Email> > </Person> > > ----The XSL to print XPath--- > <xsl:template match="Company"> > //Print the XPath of Company as /Person/Company > </xsl:template> > More templates corresponding to each element. > > How do I do this...any thoughts??? <xsl:for-each select="ancestor::*"> <xsl:value-of select="concat('/',name())"/> </xsl:for-each> <xsl:value-of select="concat('/',name())"/> If the current node is an attribute, change that last '/' to '/@' - Mike ____________________________________________________________________________ mike j. brown | xml/xslt: http://skew.org/xml/ denver/boulder, colorado, usa | resume: http://skew.org/~mike/resume/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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