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Re: how to check if each char in a given string is a l

Subject: Re: how to check if each char in a given string is a letteror a digit?
From: Joerg Heinicke <joerg.heinicke@xxxxxx>
Date: Fri, 09 Aug 2002 14:11:53 +0200
for each char
Hello Biying.

Biying Huang wrote:
Hello, everyone,
I have a string  like this:
C12H10N2

Using xlt and fo, I need to display all digit characters smaller and
lower than letters.
To check if a  character in the string is a digit, I have the code like
this:
<xsl:template name="formatFormula">
  <xsl:param name="formula"/>

  <xsl:if test="string-length($formula)>0">
  <xsl:variable name="firstChar">
    <xsl:value-of select="substring($formula,1,1)"/>
  </xsl:variable>

Better use <xsl:variable name="firstChar" select="substring($formula,1,1)"/> to avoid RTF.



<xsl:choose>


    <!-- ???? Not work as I want ??? -->
    <xsl:when test="translate($firstChar,'0123456789','9')='9'">

You have to transform the other numbers to 9 too:


<xsl:when test="translate($firstChar,'0123456789','9999999999')='9'">

translate() translates char by char.


<fo:inline font-size="8" color="red" vertical-align="sub"><xsl:value-of select="$firstChar"/></fo:inline> </xsl:when> <xsl:otherwise> <fo:inline font-size="10"><xsl:value-of select="$firstChar"/></fo:inline> </xsl:otherwise> </xsl:choose> </xsl:if>

  <!-- calling itself recursively -->
  <xsl:if test="string-length($formula)>1">
    <xsl:call-template name="formatFormula">
      <xsl:with-param name="formula">
        <xsl:value-of select="substring($formula, 2)"/>
      </xsl:with-param>

Again better use <xsl:with-param name="formula" select="substring($formula, 2)"/>


    </xsl:call-template>
  </xsl:if>
</xsl:template>


But the result is that only the char '0' get translate and thus get detected as a digit. All other digits are not detected. Any better solutions?


Thanks in advance for your help.


Biying


--

System Development
VIRBUS AG
Fon  +49(0)341-979-7419
Fax  +49(0)341-979-7409
joerg.heinicke@xxxxxxxxx
www.virbus.de


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