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Re: how to check if each char in a given string is a l
Subject: Re: how to check if each char in a given string is a letteror a digit?
From: Joerg Heinicke <joerg.heinicke@xxxxxx>
Date: Fri, 09 Aug 2002 14:11:53 +0200
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Hello Biying.
Biying Huang wrote:
Hello, everyone,
I have a string like this:
C12H10N2
Using xlt and fo, I need to display all digit characters smaller and
lower than letters.
To check if a character in the string is a digit, I have the code like
this:
<xsl:template name="formatFormula">
<xsl:param name="formula"/>
<xsl:if test="string-length($formula)>0">
<xsl:variable name="firstChar">
<xsl:value-of select="substring($formula,1,1)"/>
</xsl:variable>
Better use <xsl:variable name="firstChar" select="substring($formula,1,1)"/>
to avoid RTF.
<xsl:choose>
<!-- ???? Not work as I want ??? -->
<xsl:when test="translate($firstChar,'0123456789','9')='9'">
You have to transform the other numbers to 9 too:
<xsl:when test="translate($firstChar,'0123456789','9999999999')='9'">
translate() translates char by char.
<fo:inline font-size="8" color="red"
vertical-align="sub"><xsl:value-of select="$firstChar"/></fo:inline>
</xsl:when>
<xsl:otherwise>
<fo:inline font-size="10"><xsl:value-of
select="$firstChar"/></fo:inline>
</xsl:otherwise>
</xsl:choose>
</xsl:if>
<!-- calling itself recursively -->
<xsl:if test="string-length($formula)>1">
<xsl:call-template name="formatFormula">
<xsl:with-param name="formula">
<xsl:value-of select="substring($formula, 2)"/>
</xsl:with-param>
Again better use <xsl:with-param name="formula" select="substring($formula,
2)"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
But the result is that only the char '0' get translate and thus get
detected as a digit. All other digits are not detected. Any better
solutions?
Thanks in advance for your help.
Biying
--
System Development
VIRBUS AG
Fon +49(0)341-979-7419
Fax +49(0)341-979-7409
joerg.heinicke@xxxxxxxxx
www.virbus.de
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