[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] getting distinct content from list (?)
Hi, The least of my xslt problems at the moment is this one (I have others which I'm sure I'll come back to ;). This is probably easy but I just can't see it. Here it goes. I have an xpath which results in a list like: 'cynthia', 'bob', 'janet', 'bob', 'jack', 'bob', 'jack'. These are user IDs collected from different locations in a document. The actual xpath is: notify/@user | /ming/users/user[@global-notify='yes']/@id | /ming/client[@id=$myClient]/admin/@user I need to output this as: "bob, cynthia, jack and janet". Without the duplicates (sorted and xslt 1.0). How? Thanks, -Kurt. __________ kurt george gjerde <kurt.gjerde@xxxxxxxxxxxxxxxxx> intermedia uib, university of bergen Free Jon - http://www.efn.no/freejon01-2002.html XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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