Re: Converting XML to HTML using a XSLT stylesheete??

tpchen wrote:
>      I have some problem with libxslt. I try to transform the xml file into another form with the following two files(one is an xml file, 
> and the other is the xslt file.) I hope to get ?SignatureValue? from the transform. But I don't know what's wrong. Would anyone be kind 
> enough to tell me how to solve it. Any suggestion is appreciated. Thanks a lot....
>   
>  tpchen
>  
> ======================== XSL FILE : Test.XSL=================================
> http://210.242.21.129/nbca-download/test.xsl
>  
> ======================== XML FILE : Test.XML=================================
> http://210.242.21.129/nbca-download/test.xml

1. The XPath expression

 Signature

means elements with *local* name Signature, in no namespace.

Your Signature elements are in the http://www.w3.org/2000/09/xmldsig#
namespace, so you have to specify that. You must use a prefix in order
to do this. Add an xmlns:dsig="http://www.w3.org/2000/09/xmldsig#" to
your xsl:stylesheet and then look for dsig:Signature, not Signature.

2.  "//" traverses the entire document looking for nodes.
You know where your dsig:Signature elements are -- they are all
at /IFX/dsig:Signature .. so use that instead of //dsig:Signature in
your xsl:apply-templates.

3.  match="//Signature" is also inefficient. Use match="dsig:Signature"

   - Mike
____________________________________________________________________________
  mike j. brown                   |  xml/xslt: http://skew.org/xml/
  denver/boulder, colorado, usa   |  resume: http://skew.org/~mike/resume/

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