[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: transforming XML into XML using XSLT.
Neel,
At 04:11 PM 8/13/2002, you wrote: Is it possible to convert XML[having useful +unnecessary data ] -----to-----> XML [having Useful data] using XSLT.Could you please help me out with an example. Sure: <source> <useful>This is an example on XSL-List</useful> <unnecessary>It's rather pointed (unnecessarily so).</unnecessary> </source> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <!-- this could be a near-identity transform, but for ease of illustration we'll just strip out the node structure instead --> <xsl:template match="/"> <result> <!-- this template is here so the result is actually XML, rather than simply a well-formed external parsed entity --> <xsl:apply-templates/> </result> </xsl:template> <xsl:template match="unnecessary"/> </xsl:stylesheet> But I think the real answer depends on what's useful and what's unnecessary, and how you tell the difference. Cheers, Wendell
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