RE: Merging two XML files

First comment: your code

          <xsl:for-each select="@*">
             <xsl:copy>
                <xsl:value-of select="." />
             </xsl:copy>
          </xsl:for-each>

is just a long-winded way of saying

          <xsl:copy-of select="@*"/>

> But what I wanted 
> to do is, without any hardcoding, I wanted to get the local-name() 
> of the current node, for example "Name", lookup in the Doc.xml 
> file, if there is any node with it's name as "Name" and then 
> merge. There shouldn't be any sort of hardcoding.

What if there's more than one node in the other document called "Name"?
You are making assumptions that the two documents have similar
structure. If you want a generic solution that makes no assumptions
about the structure of the second document, then you are going to have
to define your merging requirements very carefully.

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 





> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Kalyan Kumar Mudumbai
> Sent: 01 July 2002 10:04
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Merging two XML files
> 
> 
> Hi All, I'm new to using XSL. I have a small problem while merging 
> two xml files. I have two xml files and one xsl file which merges 
> them as shown below. And the result is also shown below
> --------------
> Input.xml
> --------------
> <?xml version="1.0" encoding="UTF-8"?>
> <Person>
>      <Name>
>          <LastName/>
>          <FirstName/>
>      </Name>
> </Person>
> -------------------
> Doc.xml
> -----------------
> <?xml version="1.0" encoding="UTF-8"?>
> <Person>
>      <Name>
>          <MiddleName/>
>      </Name>
> </Person>
> -------------------
> Merge.xsl
> -------------------
> <?xml version="1.0"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
> version="1.0">
>     <xsl:output method="xml" indent="yes" />
> 
> <!--source of data; default can be overridden on command line-->
>     <xsl:param name="source" select="'./Doc.xml'" />
> 
> <!-- Copy XSL elements and their attributes -->
>     <xsl:template match="*">
>        <xsl:copy>
>           <xsl:for-each select="@*">
>              <xsl:copy>
>                 <xsl:value-of select="." />
>              </xsl:copy>
>           </xsl:for-each>
> 
>           <xsl:apply-templates select="node()" />
>        </xsl:copy>
>     </xsl:template>
> 
>     <xsl:template match="Name">
>        <xsl:copy>
>           <xsl:for-each select="@*">
>              <xsl:copy>
>                 <xsl:value-of select="." />
>              </xsl:copy>
>           </xsl:for-each>
>           <xsl:apply-templates select="*" />
>           <xsl:apply-templates 
> select="document($source)/Person/Name/MiddleName" />
>        </xsl:copy>
>     </xsl:template>
> </xsl:stylesheet>
> -----------------------------------
> Result.xml
> -------------------------------
> <?xml version="1.0" encoding="UTF-8"?>
> <Person>
>      <Name>
>          <LastName/>
>          <FirstName/>
>          <MiddleName/>
>      </Name>
> </Person>
> ----------------------------------
> 
> So, from the two input files it is obvious that I wanted to merge 
> the leaf nodes of <Name>. I was able to do that using the above 
> Merge.xsl file, but there is a problem with that. In one of the 
> templates I had to hardcode that select="Name". But what I wanted 
> to do is, without any hardcoding, I wanted to get the local-name() 
> of the current node, for example "Name", lookup in the Doc.xml 
> file, if there is any node with it's name as "Name" and then 
> merge. There shouldn't be any sort of hardcoding. Can someone help 
> me out in doing that.
> 
>                Thanks,
> Regards,
> Kalyan
> 
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