RE: String manipulation question

Hi,

> My question is regarding some string manipulation.
> I have template which looks at a string value of a date 
> (eg 02-03-02 param1) and a dateformat (eg. DD-MM-YY param2).
> 
> My template has to (for e.g.): 
> return       02-03-02
> if  param1=  2-3-02
> and param2=  DD-MM-YY
> 
> or 
> return       02/03/2002
> if  param1=  02/3/02
> and param2=  DD-MM-YYYY    
> 
> 
> I'm having difficulties in thinking of a short and neat way 
> of appending '0'
> in front of any number between 1-9 (if its not already there). 
> [And appending a '20' for a year format (if its not already there)].
> Any help appreciated.

It's friday, so...

<xsl:template name="dateFormat">
  <xsl:param name="str" />
  <xsl:param name="date-format" />
  <xsl:choose>
    <xsl:when test="contains($str, '-')">
      <xsl:value-of select="concat(format-number(substring-before($str, '-'), substring(substring('2000', 4 - string-length(substring-before($date-format, '-'))), 1, string-length(substring-before($date-format, '-')))), '-')"/>
      <xsl:call-template name="dateFormat">
        <xsl:with-param name="str" select="substring-after($str, '-')" />
        <xsl:with-param name="date-format" select="substring-after($date-format, '-')" />
      </xsl:call-template>
    </xsl:when>
    <xsl:otherwise>
      <xsl:value-of select="format-number($str, substring(substring('2000', 4 - string-length($date-format)), 1, string-length($date-format)))"/>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>

I'll also format YYYY-MM-DD.

Cheers,

Santtu

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