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Re: logical and in selection expression possible?
Subject: Re: logical and in selection expression possible?
From: Joerg Heinicke <joerg.heinicke@xxxxxx>
Date: Sat, 20 Jul 2002 02:15:51 +0200
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Templates are applied for every root element in the node set returned by
the key(). If a key('key', 'rulekey1') returns more than one node, "the
template is being activated twice". With the union operator | you merge
two node sets, i.e. a node that is member of both node sets is only once
contained in the unioned node set.
But this seems more or less uninteresting in your case. I assume you
want to do something completely different. You only want to "collect"
the nodes and operate with them in one template? Then
<xsl:call-template> could be the choice while passing the keys to the
template via a parameter:
<xsl:call-template name="foo">
<xsl:with-param name="bar" select="key('key', 'rulekey1') |
key('key', rulekey2')"/>
</xsl:call-template>
<xsl:template name="foo">
<!-- default value: empty node set -->
<xsl:param name="bar" select="/.."/>
...
</xsl:template>
But a more concrete explanation of your problem can help.
Regards,
Joerg
Alex Reuter wrote:
Ok, I've run into a bit of a snag.
When I am passing the union of the nodesets to the applied template, it
appears that the template is being activated twice. I was hoping to be
able to access both nodesets at the same time.... unless they are the
children of the same parent, is this impossible?
Thanks,
Alex
From: David Carlisle <davidc@xxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: logical and in selection expression possible?
Date: Thu, 18 Jul 2002 17:17:29 +0100
<xsl:apply-templates select="key('key', rulekey1') and key('key',
'rulekey2') "/>
you want | there not and and is a boolean operator so this expression
will evaluate to true or false. but a select expression needs a node
set.
<xsl:template match="rule and rule2">
ditto.
David
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