Re: Re: Grouping using a Child Node....

Thanks All,
  I am able to solve ir using Muenchian technique using Key

Thanka a Lot,
Prince

agreed :) ..

From: Mike Brown <mike@xxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  Grouping using a Child Node....
Date: Mon, 24 Jun 2002 03:39:52 -0600 (MDT)

Vasu Chakkera wrote:
> Prince,
> The following code will help you..
>
> <?xml version="1.0"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> <xsl:template match="/">
> <xsl:for-each select="/items/item[not(type=preceding-sibling::item/type)]">
> <b><u><i>The Details of <xsl:value-of select="./type"/></i></u></b><br></br>
> <xsl:for-each select="/items/item[./type = current()/type]">
> <xsl:value-of select="./name"/>--------<xsl:value-of
> select="./value"/><br></br>
> </xsl:for-each>
> <hr></hr>
> </xsl:for-each>
> </xsl:template>
> </xsl:stylesheet>

There's no harm in the above, but I thought I'd point out that

- "./" is redundant and can be omitted.

- "<br></br>" & "<hr></hr>" can be shortened to "<br/>" & "<hr/>".

- If the output is to be serialized as HTML, <xsl:output method="html"/>
would be prudent.

- Mike
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