Re: RE: how I can select the largest attribute value

That will not serve the purpose...
u have to select the first among the sorted..
so the following code would help...

hope this help
Vasu

From: Henk Meulekamp <henkm@xxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: "'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'" <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject:  RE: how I can select the largest attribute value
Date: Tue, 18 Jun 2002 16:35:22 +0200

Maybe you can do something like this?

<xsl:for-each select="Root/element[1]">
	<xsl:sort select="@length" data-type="number" order="descending"/>
		<xsl:value-of select="@length"/>
</xsl:for-each>

| -----Original Message-----
| From: Bodrul Haque [mailto:Bodrul.Haque@xxxxxxxxxxxxxxxxxxxxxxx]
| Sent: dinsdag 18 juni 2002 16:23
| To: 'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'
| Subject:
|
|
| Hi List,
|
| Can someone please tell me how I can select the largest
| attribute value from the following xml file, without doing
|
| <xsl:value-of select="Root/element[@length="14"]/@length" />.
|
| (I don't want to use a hard coded value in the predicate). Is
| there an Xpath that i can use. Xml file: <Root>
|      <element  length="3" />
|      <element  length="14" />
|      <element  length="1" />
|      <element  length="6" />
|      .....
| </Root>
|
| I'm using MSXML3.
|
| Thanks in Advance
|
| Bodrul
|
|
|
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