[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: is it possible to construct new xml with xsl ?
hi yeah well i know that , but the thing is that im loading xml files not xsl ... so if i load the xsl its fine ... but when i load the xml whit the xsl linked its not working .. i need it to be outputted in as new xml . tnx ----- Original Message ----- From: "Sebastian Rahtz" <sebastian.rahtz@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Sunday, June 16, 2002 1:20 PM Subject: Re: is it possible to construct new xml with xsl ? > On Mon, Jun 17, 2002 at 10:46:37AM -0700, Meir wrote: > > > > ******************************** THE XSL ******************************* > > <xsl:stylesheet version="1.0" > > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > > <xsl:template match="/"> > > > > <![CDATA[<?xml version="1.0"?>]]> > > <![CDATA[<myroot>]]> > > just omit all the <![CDATA[ and ]]> from your .xsl file. if you > say > <myroot> > then > <myroot> > goes into the output. > > you are misunderstanding fairly fundamentally how XSLT works..... > -- > Sebastian Rahtz OUCS Information Manager > 13 Banbury Road, Oxford OX2 6NN. Phone +44 1865 283431 > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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