Re: Elements of non-actual position

<xsl:template match="table/rows">
  <xsl:for-each select="row">
    <xsl:variable name="pos" select="position()"/>
    <xsl:if test="/table/cols/col[$pos]/@visible = '1'">
      do what you want
    </xsl:if>
  </xsl:for-each>
</xsl:template>

Hi, I have a problem of searching in my XML data:
<table>
<cols>
<col visible="1"/>
<col visible="1"/>
<col visible="1"/>
<col visible="0"/>
<col visible="1"/>
<col visible="1"/>
<col visible="0"/>
</cols>
<rows>
<row>
<cell>1</cell>
<cell>2</cell>
<cell>3</cell>
<cell>4</cell>
<cell>5</cell>
<cell>6</cell>
<cell>7</cell>
</row>
<row>
...
</row>
...
</rows>
</table>

and if I have a template:

<xsl:template match="table/rows">
  <!-- and I want in for-each: Give me all elements cell which position is the same as the position of elements cols which attribute visible is 1 -->
  <xsl:for-each="...">
    <!-- than this for-each must contain: cell 1, cell 2, cell 3, cell 5, cell 6 -->

  </xsl:for-each>
</xsl:template>

I have no idea how I can get elements, one element I can...
Thanks very much
Rudolf