Re: Sorting XML with XSL, output as XML

<xsl:template match="*|text()|@*">
  <xsl:copy>
    <xsl:apply-templates select="*|text()|@*"/>
  </xsl:copy>
</xsl:template>

<xsl:template match="book">
  <xsl:copy>
    <xsl:apply-templates select="@*"/>
    <xsl:apply-templates select="chapter">
      <xsl:sort select="*[name()=$sortfield]" order="{$sortorder}" />
    </xsl:apply-templates>
  </xsl:copy>
</xsl:template>

Hi all,

I'm new it this so I hope I'm posting this message the right way. Anyway...

I've got a HTML-pager with a table, with a data island, so the XML data is bounded in the table by Datafld and Datasrc. Now I want to sort the XML-data by an XSL-file and a XSL:SORT command. However, this needs to be generic so I can use the same XSL for all kinds of XML, because else I have to make a XSL for every XML.

Example:
	<?xml version="1.0"?>
	<book>
	<chapter>
	<number>2</number>
	<title>two</title>
	<paragraph>text 2</paragraph>
	</chapter>
	<chapter>
	<number>1</number>
	<title>one</title>
	<paragraph>text 1</paragraph>
	</chapter>
	</book>

How do I sort this data by e.g. Number or by Title in a generic way. It's needs to output the "same" XML but sorted like:

	<?xml version="1.0"?>
	<book>
	<chapter>
	<number>1</number>
	<title>one</title>
	<paragraph>text 1</paragraph>
	</chapter>
	<chapter>
	<number>2</number>
	<title>two</title>
	<paragraph>text 2</paragraph>
	</chapter>
	</book>

I know how to sort with xsl:param and <xsl:sort select="@*[name()=$sortfield]" order="{$sortorder}" /> but how do I get the XML back like the XML described above...???

I've spend a lot of this on this so I would greatly appreciate any help!!

Thanks,
Ernst Wolthaus