Stuck with Jeni's Logic...Help me out..!!

Hi Jeni and Hi all..
   My need is to get a different of A (xml file) and B (xml File) and then
get C (as xml file).

   I used the logic explained in the below link as jeni explained it.

   http://sources.redhat.com/ml/xsl-list/2000-07/msg00320.html

   Still not able to get a clear picture upon it.

   When telling about XML files i can post it when anone wish to see it .
   Let me have a reply upon this.

   Sample XML is below:

   A.xml.
  -------
<RecipeVersions>
<RecipeVersion>
<VersionID>{007A6506-B4E1-4F2C-B4CD-A725B41DDA33}</VersionID>
<BodySize>100</BodySize>
<Identifier>Anoop&gt;/RBClass1/Test111</Identifier>
<Version>1</Version>
</RecipeVersion>
<RecipeVersion>
<VersionID>{010EA2DE-1063-47B8-82FF-4D15EA0BCA2A}</VersionID>
<BodySize>100</BodySize><Identifier>Anoop&gt;/RBClass1/Test198</Identifier>
<Version>1</Version></RecipeVersion>
<RecipeVersion><VersionID>{1ED0B241-862C-4803-98BF-8E1385A38AAE}</VersionID>
<BodySize>100</BodySize><Identifier>Anoop&gt;/RBClass1/Test134</Identifier><
Version>1</Version></RecipeVersion>
</RecipeVersions>

  In the similar way b.xml will be there. Based on VersionID I need to
compare A wish B and put into C elements of A which is not found in B.xml.


  Hoping to get a reply.


Thanks in advance

Sachi..




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