Re: How can i convert the variable value into xpath

Mike B.,
Thanks alot! that is exactly what I needed. I decided that using
documents was alot better than using prefixed tags (below). I have
created these bogus examples to see how I can write just this one
function and get it to work. I will add the other filters later.


Much in debt,
Mike F.

XSL:
<xsl:template match="/">
  <XC1011>
    <xsl:apply-templates select="//C1011"/>
  </XC1011>
</xsl:template>

<xsl:template match="C1011">
  <xsl:variable name="array" select="document('LLP.xml')//myitem"/>
    <xsl:for-each select=".">
      <xsl:variable name="getit" select="."/>
        <xsl:for-each select="$array">
          <xsl:variable name="item" select="node()"/>
            <xsl:if test="$getit = $item">
              <xsl:copy-of
select="document('UUL.xml')//var[@name=current()/@LINK]/node()"/>
            </xsl:if>
          </xsl:for-each>
        </xsl:for-each>
</xsl:template>

LLP.xml:
<LLP>
<myitem LINK="r1">[Letter] included in We're staying here *in* I
Remember Mama *root* RODGERS1</myitem>
<myitem LINK="r2">[Lyric sheets and lyric sketches for Me and Juliet]
*in* Me and Juliet *root* RODGERS1</myitem>
<myitem LINK="r3">[Lyric sheets for I Remember Mama] *in* I Remember
Mama *root* RODGERS1</myitem>
</LLP>


UUL.xml:
<UUL>
<var name="r1"><B>[Letter...r1]</B> </var>
<var name="r2"><U>[Lyric sheets...r2]</U></var>
<var name="r3"><S>[Lyric sheets for...r3]</S></var>
</UUL>


XML (source):
<UL>
  <C1011>[Letter] included in We're staying here *in* I Remember Mama
*root* RODGERS1</C1011>
  <C1011>[Lyric sheets and lyric sketches for Me and Juliet] *in* Me
and Juliet *root* RODGERS1</C1011>
  <C1011>[Lyric sheets for I Remember Mama] *in* I Remember Mama
*root* RODGERS1</C1011>
</UL>

OUTPUT:
<XC1011>
   <B>[Letter...r1]</B> 
   <U>[Lyric sheets...r2]</U>
   <S>[Lyric sheets for...r3]</S>
</XC1011>


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