[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] How to pass search path as variable and get back node
I have searched FAQ section and can not find answer. I know it must be there but I can not find it. Please excuse the redundant question. Can't figure out how to pass search path as variable and get back node list. I get back search string value instead of node list. <xsl:param name="DATA_REQUEST_NAME"/> <xsl:variable name="ftype_search" select="concat('//JOB_REQUEST/DATA_REQUEST[@NAME=',$DATA_REQUEST_NAME,']/FILE_TYPE')"/> <xsl:variable name="chosen_ftype" select="$ftype_search"/> xsl:value-of select="$chosen_ftype"/> Returns //JOB_REQUEST/DATA_REQUEST[@NAME=DATAREQUEST4]/FILE_TYPE How can I get the node list returned instead of the string? XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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