[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Sorting wiht variable number of sort keys
You could do this using some kind of recursive algorithm that does one sort (into a temporary tree) on each recrsive step, but it sounds horrible. I think this is a case for generating the stylesheet dynamically from the sort specification. Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of > Robert_Wittigayer@xxxxxx > Sent: 31 January 2002 16:45 > To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx > Subject: Sorting wiht variable number of sort keys > > > Hi all, > > I have an XML file like this > and I try to sort some rows using the sort keys > defined in <sortinfo>. > > > <!-- THIS ARE THE SORT KEYS --> > <!-- THE NUMBER OF THE KEYS IS NOT FIXED--> > > <sortinfo> > <sortkey1/> > <sortkey2/> > ... > ... > <sortkeyN/> > > </sortinfo> > > .... > > > <row> > > <col> 63 </col> > <col> 32 </col> > > <sortkey1> 10 </sortkey1> > <sortkey2> 15 </sortkey1> > ... > ... > <sortkeyN> 11 <sortkeyN/> > > > </row> > > <row> > > <col> 51 </col> > <col> 30 </col> > > <sortkey1> 10 </sortkey1> > <sortkey2> 13 </sortkey1> > ... > ... > <sortkeyN> 20 <sortkeyN/> > > </row> > > > can somebody tell me how can I reach something like: > > > <xsl:for-each select="//row"> > > <!-- THIS MUST DEPEND ON <sortinfo> --> > > <xsl:sort select="sortkey1"> > </xsl:sort> > > <xsl:sort select="sortkey2"> > </xsl:sort> > ... > ... > > <xsl:sort select="sortkeyN"> > </xsl:sort> > > </xsl:for-each> > > > Thanks, > > Robert. > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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