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RE: adding unique values to a drop-down list
Subject: RE: adding unique values to a drop-down list
From: "Katie McNally" <kmcnally9@xxxxxxxxxxx>
Date: Tue, 04 Dec 2001 14:50:35 -0600
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I have not been able to correctly fill the drop-down with brokers. The
drop-down must contain the broker name/id combinations listed alphabetically
with no duplicates.
The first time I followed your suggestion but the drop down did not contain
any brokers. My for-each statement:
<xsl:for-each select="Loan[not(.=preceding-sibling::*) and
string(BrokerSet/Broker/Name) and string(BrokerSet/Broker/Id)]">
<option value="{BrokerSet/Broker/Id}"><xsl:value-of
select="BrokerSet/Broker/Name"/> - <xsl:value-of
select="BrokerSet/Broker/Id"/></option>
</xsl:for-each>
I modified the for-each. The drop-down contained brokers, but they were not
listed alphabetically, and duplicates were present. My for-each:
<xsl:for-each select="Loan/BrokerSet/Broker[not(.=preceding-sibling::*) and
string(Name) and string(Id)]">
<option value="{Id}"><xsl:value-of select="Name"/> - <xsl:value-of
select="Id"/></option>
</xsl:for-each>
I added sort statements. The drop-down contained brokers, listed
alphabetically, but duplicates were present. My for-each:
<xsl:for-each select="Loan/BrokerSet/Broker[not(.=preceding-sibling::*) and
string(Name) and string(Id)]">
<xsl:sort select="Name"/>
<xsl:sort select="Id"/>
<option value="{Id}"><xsl:value-of select="Name"/> - <xsl:value-of
select="Id"/></option>
</xsl:for-each>
I cannot figure out how NOT to display duplicates. Any suggestions?
From: "kfricovsky" <kfricovsky@xxxxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject: RE: adding unique values to a drop-down list
Date: Tue, 4 Dec 2001 12:18:19 -0500
This will work for you. I used <funds> as my root element.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>
<xsl:template match="fund">
<form action="">
<select name="FOO">
<xsl:for-each select="Loan[not(.=preceding-sibling::*)
and string(BrokerSet/Broker/Name) and string(BrokerSet/Broker/Name)]">
<option
value="{BrokerSet/Broker/Id}"><xsl:value-of
select="BrokerSet/Broker/Name" /> - <xsl:value-of
select="BrokerSet/Broker/Id" /></option>
</xsl:for-each>
</select>
</form>
</xsl:template>
</xsl:stylesheet>
-Kevin Fricovsky
-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Katie
McNally
Sent: Tuesday, December 04, 2001 11:45 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: adding unique values to a drop-down list
I have xml that contains loans and their data (which includes broker
name
and id).
I need to add a drop-down of brokers to my page. Each selection in the
list
box needs to display "Broker Name - Broker Id" and the value of each
selection must be set to the Broker Id. These selections must be listed
alphabetically, with only unique values displayed (no duplicates).
For example:
Example XML:
<Loan>
<BrokerSet>
<Broker>
<Name>ABC Broker</Name>
<Id>123456</Id>
</Broker>
</BrokerSet>
</Loan>
<Loan>
<BrokerSet>
<Broker>
<Name>LMN Broker</Name>
<Id>345678</Id>
</Broker>
</BrokerSet>
</Loan>
<Loan>
<BrokerSet>
<Broker>
<Name/>
<Id/>
</Broker>
</BrokerSet>
</Loan>
<Loan>
<BrokerSet>
<Broker>
<Name>LMN Broker</Name>
<Id>345678</Id>
</Broker>
</BrokerSet>
</Loan>
<Loan>
<BrokerSet>
<Broker>
<Name>ABC Broker</Name>
<Id>999999</Id>
</Broker>
</BrokerSet>
</Loan>
For the xml listed above, the list box should contain the following
values: All Brokers ABC Broker - 123456 ABC Broker - 999999 LMN Broker -
345678
How do I fill the list box with only unique selections which consist of
broker name/broker id combinations?
How do I handle loans that do not have broker name or id data?
Thanks,
Katie
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