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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Using xsl to test value of node
 Hi David,
Many thanks for your help, that makes much more sense now.
The parser still throws up the following error:
"The element type "xsl:template" must be terminated by the matching
end tag </xsl:template>" at the following position
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="html"/>
<xsl:template match="LOG">
<xsl:apply-templates select="DIRECT"/>
</xsl:template>
<xsl:template match="DIRECT">
<xsl:apply-templates select="CHARACTER_ID"/>
</xsl:template>
<xsl:template match ="CHARACTER_ID">
<xsl:if test=".=44639"/>
<xsl:apply-templates select="../LOCATION_ID"/>
</xsl:if> *here*
</xsl:template>
<xsl:template name="LOCATION_ID">
<html>
<body>
<h1>
<xsl:value-of select="."/>
</h1>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Its as if it can't see the </xsl:template> tag underneath.
Am I missing something blatant! Probably!!
Cheers again
Ahmad
David Carlisle wrote:
>
> <xsl:if test() ="44639"/>
> XSL stylesheets have to be XML XML attribute names can't include ()
> so this won't get past the XML parser, so the xslt engine won't see the
> stylesheet. You want
> <xsl:if test=".=44639"/>
>
> <xsl:Xpply-templates select="LOCATION_ID"/>
> in that template the current node is CHARACTER_ID so the above XPath
> would select LOCATION_ID children of CHARACTER_ID nodes, but there are
> not any, you want
> <xsl:Xpply-templates select="../LOCATION_ID"/>
>
> David
>
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--
-----------------------------------------------------
Ahmad J. Reeves BSc(Hons), MSc(Dist). Phd Student
Information, Media, and Communication Research Group,
Dept of Computer Science,Queen Mary,University of London,
E1 4NS Tel +44 (0)20 7882 5257
http://www.dcs.qmw.ac.uk/imc/
-----------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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