A riddle...

Hello all,

i don't see the solution, although there must be one.

I'm transforming XML to HTML. This is an example XML:

<root>
 <tree>
  <leaf idUeber="102149" />
  <node idUeber="102150">
   <leaf idUeber="102160" />
   <leaf idUeber="102165" />
   <leaf idUeber="102166" />
   <leaf idUeber="102173" />
   <leaf idUeber="102174" />
   <leaf idUeber="102175" />
  </node>
  <leaf idUeber="102151" />
  .
  .
  . etc...
  .
 </tree>
 <objects>
  <Menuestruktur webID="102149">
   <moreinfo>
  </Menuestruktur>
  <Menuestruktur webID="102150">
   <moreinfo>
  </Menuestruktur>
  <Menuestruktur webID="102151">
   <moreinfo>
  </Menuestruktur>
  <Menuestruktur webID="102152">
   <moreinfo>
  </Menuestruktur>
  .
  .
  . etc...
  .
 </objects>
</root>


This is what I want to do:

I want to select every Menuestruktur-Element with a webID that is found in
the tree-part of the structure as child of a 'node'-Element with a given
idUeber-Attribute stored in a variable $wid.

With

<xsl:apply-templates select="/root/objects/Menuestruktur
          [@webID=/root/tree/*[@idUeber=$wid]/*/@idUeber]"/>

I manage to do that. Now comes the catch:

I just want every SECOND Menuestruktur-Element that is a leaf in the
tree-part of the XML. That is, the result should be

<Menuestruktur webID="102160"/>
<Menuestruktur webID="102166"/>
<Menuestruktur webID="102174"/>

This has something to do with position() mod 2 = 1, but I don't get it
right. Can anyone help me? Is there an alternative way?

Thanks in advance,
Christian

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