Re: namespace-uri() method returns emty,using xalan 2.

Hey list:

 i am using Xalan 2.0 processor.
Using this ,

if i use method1 it doesnt match the template 'a:root' at all.I get an empty document.

if i use method2: it matches the template but i get namespace-uri() empty.

Is this the problem with xalan 2.0??

can any body test with xalan 2.0 and reply me?

Thanks
challa sumalatha


> Date: Tue, 13 Nov 2001 10:39:43 +0200
> From: Oleg Tkachenko <olegt@xxxxxxxxxxxxx>
> Subject: Re:  namespace-uri() method returns emty,
> using xalan 2.0
> 
> challa sumalatha wrote:
> 
> > Hey list:
> > i tried with all of the following options to get the 
> namespace-uri(),all of my efforts are in vain.In all of 
> these cases it returns empty.Help needed....
> 
> > xml:
> > <?xml version="1.0"?>
> >  <a:root xmlns:a="name-a">
> >  	<b:sub xmlns:b="name-b"/>
> >  	<c:sub xmlns:c="name-c"/>
> >  </a:root>
> > xsl:method1:
> > <?xml version="1.0"?>
> >  <xsl:stylesheet
> >  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
> >  version="1.0"
> >    xmlns:a="name-a"  xmlns:b="name-b"  
> >  xmlns:c="name-c">
> >  <xsl:template match="/">
> >    <xsl:for-each select="a:root">
> >     <uri><xsl:value-of select="namespace-uri()
> "/></uri>
> >   </xsl:for-each>
> >  </xsl:template>
> >  </xsl:stylesheet>
> 
> This one works fine for me on msxml3 and saxon and 
> because of its 
> simplicity it have to work :) I got
> <uri xmlns:a="name-a" xmlns:b="name-b" 
> xmlns:c="name-c">name-a</uri>
> 
> 
> > xsl: method:2
> > <?xml version="1.0"?>
> >  <xsl:stylesheet
> >  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
> >  version="1.0"
> >    xmlns:a="name-a"  xmlns:b="name-b"  
> >  xmlns:c="name-c">
> >  <xsl:template match="/">
> >    <xsl:for-each select="*[name()='a:root']">
> 
> This is XPath syntax error - predicate always requires 
> nodetest, you 
> probably mean *[name()='a:root'], which is tough 
> version of a:root.
> I guess the problem is in your processor, which one are 
> you using?
> 
> 
> - -- 
>

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